So much for this rod.

[SlugSlinger]

Anode rod that is.

Waited way to long to change this out in the old water heater.

This is what they look like new. 3/4 x 40”.

 

[TwoShoots]

Dang, she gone!

I just did this on mine too. 10 years worth of corrosion and it looked like this stock photo.

Did you go back with one of those new linked ones that look like sausage or another full length model?
I went with the linked model and it was easy as pie getting it loaded back in.

 

[SlugSlinger]

Dang, she gone!

I just did this on mine too. 10 years worth of corrosion and it looked like this stock photo.

Did you go back with one of those new linked ones that look like sausage or another full length model?
I went with the linked model and it was easy as pie getting it loaded back in.

I had plenty of room for the stock length. I went with the factory replacement.

 

[turkeyrun]

Got your money's worth.
No need to change until it's time.

 

[Mr.Glock]

Ya’ll on City Water?

 

[dennishoddy]

Ya’ll on City Water?

I may be 100% wrong, but our old RV needed the anode changed at least annually.
The new RV has the same anode for three years and it’s still in almost new condition.
My only thoughts about this is that there are internal issues that cause quick failures of anodes, like lack of dielectric isolation and so on?
Just my speculation

 

[SlugSlinger]

Ya’ll on City Water?

Rural water that is sourced from the verdigris river. The water is full of limestone. The refrigerator tray under the water dispenser needs decalcified every few months.

 

[crapsguy]

Anode rod that is.

Waited way to long to change this out in the old water heater.

View attachment 530834

This is what they look like new. 3/4 x 40”.


View attachment 530844

I don't know how old that tank is but if it is 15+ you might consider replacing it soon -- it is the pits to find your tank leaking when it is 10 degrees outside. even if it is still working ok- the bottom1/4 is likely full of sediment and it's not performing very efficient = the new tank will likely return much of its cost in efficiency