You could use the small 6V lead acid battery and a solar trickle charger to keep it up.
You could use the small 6V lead acid battery and a solar trickle charger to keep it up.
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Older Chrysler products had voltage reducers from 12v to 6v. Go to NAPA and order an Echlin ICR13. Usually less than 15 bucks.
Sorry to contradict ya on this one but DON'T do this. Just like alank2 said that part is just a resistor. its value was specifically calculated for an automotive ignition coil which draws between 10 and 12 amps. I HIGHLY doubt that your camera even comes close to 250ma or 0.25 amps ..... Use Ohms law to calculate the value of your resistor and then your output voltage when you apply your cameras load......Older Chrysler products had voltage reducers from 12v to 6v. Go to NAPA and order an Echlin ICR13. Usually less than 15 bucks.
You could use the small 6V lead acid battery and a solar trickle charger to keep it up.
Are you building a robot, or a really low RPM corn shucker?
Hi,
This approach uses a resistor to convert from 12V to 6V and the problem is that the extra 6V is all wasted in the resistor as heat. You would only get half of the battery capacity this way. Then again, if you have a huge battery and don't care that might be workable.
A switching DC-DC converter will use the power in a much more efficient way. For example if the draw of the cameria is 1 amp @ 6 volts, the ICR13 is going to use 1 amp @ 12 volts with extra voltage being converted (wasted) to heat in the resistor. A DC-DC converter will only draw near 1/2 amp @ 12 volts and convert it to 1 amp @ 6 volts for example. In reality they are only 90% efficient, etc. Here is one:
http://search.digikey.com/scripts/DkSearch/dksus.dll?Detail&name=PT78ST106V-ND
You might also call interstate at this number 918-610-0007, tell them you are looking for a 6V sealed lead acid battery and ask what capacities they have and what prices.
Good luck,
Alan
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