Math Problem!

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THAT Gurl

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A wise man admits he does not understand a woman's thought process?

Can I TELL you how many times in the last 25 years Grumpy and I have had a 2 second interaction turn into a 45 MINUTE "CONVERSATION" because the man cannot do basic logical deduction?!?!?! :scream: He drives me NUTS ... It's like talking to someone who fell into a coma in 1900 and woke up TODAY!! Argh ... 🤦🤦🤦🤦🤦🤦
 

Perplexed

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Can I TELL you how many times in the last 25 years Grumpy and I have had a 2 second interaction turn into a 45 MINUTE "CONVERSATION" because the man cannot do basic logical deduction?!?!?! :scream: He drives me NUTS ... It's like talking to someone who fell into a coma in 1900 and woke up TODAY!! Argh ... 🤦🤦🤦🤦🤦🤦

You mean like this?

IMG_6038.png
 

trekrok

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I figured out a formula for this particular situation. There are two possible outcomes - male and female - and N is the number of plants in the group. The total number of possible permutations then is 2^N; you then subtract the two extreme outcomes (all male or all female) from the total, and divide the remainder by the total, and multiply by 100 to get the probability:

[(Total-2)/Total] * 100

So in the case of six plants, the formula then becomes:

2^6 = 64

[(64-2)/64] * 100 = 96.875

Thus, the probability of getting berries from a group of six plants is close to 97%.

By the way - you will never achieve 100% probability of getting berries, no matter how big the group of plants becomes. You can add so many plants to the group that the odds of getting all males or all females becomes vanishingly small, but you’ll never get rid of that possible outcome ;)
I'd feel better if you were at 99%. How many are required to get you to that threshold?
 

HillsideDesolate

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Chicks are easily sexed, 100% can be achieved.

Mixed will always be mostly roosters.

With bushes and getting, 6 bushes has 8 possibilities, with 6 having opportunities for berries.6/8 = 75% POSSIBILITY of berries.

With chicks, assume 50 - 50 mix on 100 chicks. An order for 100 chicks, 25 straight run and 75 mix pulled. Results in 25 and 50 - 25 mix. So, 2 in 3 are rooster. Order comes in for 35 and 65, nets 50 - 15.
I bought 48 mixed, at TSC and got 4 hens, with 42 roosters. 2 didn't survive.
Luckily, I was wanting meat birds, not layers. IF you want hens, pay the extra for straight run, unless you can get a helpful employee that will sex them as you go.

Son ordered 100 fertilized eggs. Hatched 54 hens and 45 roosters.

Dingleberries is a whole nuther subject, I WILL NOT get into.

Time for coffee, my head is starting to hurt.
I lost on bantams tho
 

Raido Free America

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My gf and I have an ongoing argument about the answer to this problem. Let’s say you want to acquire a plant to harvest berries from it. However, that plant needs to be in close proximity to another of the same plant, but of the opposite sex, in order for the female in the pair to produce berries. You can’t determine the sex of each plant, so you decide to bump up the odds by buying three plants and putting them in the same small garden.

What are the odds that you’ll get berries from that group of three plants? You don’t care which plant or plants produce berries; you just want to acquire berries from that group of three plants. What do you think is the answer, and how do you calculate the odds?
Are the plants from Californian, or somewhere in this country?
 

kirk1978

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After some heated debate, my gf and I realized we were arriving at the same conclusion, only in radically different ways. I have to admit, I still don’t fully understand her thought process!

And yes, we figured out the 75% chance of getting berries out of a group of three plants. I used the same method as @Okie4570 with the eight permutations, she used a 25% method of some kind and a process of elimination which somehow seemed faster.
100% chance you will lose the debate with the lady.
 

leemozoid

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My gf and I have an ongoing argument about the answer to this problem. Let’s say you want to acquire a plant to harvest berries from it. However, that plant needs to be in close proximity to another of the same plant, but of the opposite sex, in order for the female in the pair to produce berries. You can’t determine the sex of each plant, so you decide to bump up the odds by buying three plants and putting them in the same small garden.

What are the odds that you’ll get berries from that group of three plants? You don’t care which plant or plants produce berries; you just want to acquire berries from that group of three plants. What do you think is the answer, and how do you calculate the odds?
33%
 

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